C# · 12月 23, 2021

c# – 如何在Windows服务启动时运行任务?

我有一个 Windows服务,我已经编写了代码来在OnStart()事件中运行任务: protected override void OnStart(string[] args) { this.DoTask(); }private void DoTask() { Task task1 = Task.Factory.StartNew(() => this.OriginalFileProcessor.StartPolling()); try { Task.Wait(task1); } catch (Exception ex) { this.Log.Error(“Failed running the task”,ex); } }

DoTask是一个永无止境的循环.它仅在服务停止时停止.

但是当我尝试启动服务时,它会等待很长时间然后给我以下错误:

Windows Could not start the … service on Local Computer.Error 1053: The service did not respond to the start or control request in a timely fashion.

怎么解决?

解决方法 你为什么要等完你的任务?

我认为Task.Wait阻止了你当前的线程,然后你在启动服务时遇到了超时.

编辑:您需要删除此块:

try{ Task.Wait(task1);}catch (Exception ex){ this.Log.Error(“Failed running the task”,ex);}

Task.Wait确实阻止了你当前的线程.根据MSDN:

Task.Wait Method

Waits for the Task to complete execution.

编辑2改为执行此操作

Task task1 = Task.Factory.StartNew(() => this.OriginalFileProcessor.StartPolling()).ContinueWith( t =>{ var aggException = t.Exception.Flatten(); foreach(var ex in aggException.InnerExceptions) this.Log.Error(“Failed running the task”,ex);},TaskContinuationOptions.OnlyOnFaulted);