C# · 12月 25, 2021

c#读取xml文件到datagridview实例

复制代码 代码如下:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.IO;
using System.Xml;
using System.Xml.Linq;

namespace QueryXMLByLINQ
{
public partial class Frm_Main : Form
{
public Frm_Main()
{
InitializeComponent();
}

static string strPath = “Employee.xml”;
static string strID = “”;

//窗体加载时加载XML文件
private void Form1_Load(object sender,EventArgs e)
{
getXmlInfo();
}

//显示选中XML节点的详细信息
private void dataGridView1_CellClick(object sender,DataGridViewCellEventArgs e)
{
strID = dataGridView1.Rows[e.RowIndex].Cells[3].Value.ToString();//记录选择的职工编号
XElement xe = XElement.Load(strPath);//加载XML文件
//使用LINT从XML文件中查询信息
IEnumerable<XElement> elements = from PInfo in xe.Elements(“People”)
where PInfo.Attribute(“ID”).Value == strID
select PInfo;
foreach (XElement element in elements)//遍历查询结果
{
text@R_319_2419@11.Text = element.Element(“Name”).Value;//显示职工姓名
combo@R_319_2419@1.SelectedItem = element.Element(“Sex”).Value;//显示职工性别
text@R_319_2419@12.Text = element.Element(“Salary”).Value;//显示职工薪水
}
}

#region 将XML文件内容绑定到DataGridView控件
/// <summary>
/// 将XML文件内容绑定到DataGridView控件
/// </summary>
private void getXmlInfo()
{
DataSet myds = new DataSet();
myds.ReadXml(strPath);
dataGridView1.DataSource = myds.Tables[0];
}
#endregion
}
}

复制代码 代码如下:
<?xml version=”1.0″ encoding=”UTF-8″?>
-<Peoples> -<People ID=”001″> <Name>小王</Name> <Sex>男</Sex> <Salary>1500</Salary> </People> -<People ID=”002″> <Name>小吕</Name> <Sex>男</Sex> <Salary>1500</Salary> </People> -<People ID=”003″> <Name>小梁</Name> <Sex>男</Sex> <Salary>1500</Salary> </People> </Peoples>